kourosh89 (November 30, 1999 at 12:00 am)

I have an easier way of finding h(y). 1) Remove all terms containing x from N 2) h(y) is the antiderivative of the remaining terms

auralacuity (November 30, 1999 at 12:00 am)

I get tripped up at 5:30 (also new to implicit differentiation). Taking the derivative of (x^2*y) gives (2xy + x^2y'), but I'm not clear on how the chain rule was applied. It does look like the product rule though. Is that possibly what was meant?

PCGamerPortal (November 30, 1999 at 12:00 am)

@luischuchopepe UNAM?

kewlgeko (November 30, 1999 at 12:00 am)

wow I'm finally understanding things. I wish our teacher didnt BS through alot of stuff and just told us straight forward like this.

brco2003 (November 30, 1999 at 12:00 am)

Why do you need to change the original form? Isn't ___dx + ___dy = 0 what we want?

immortal6699 (November 30, 1999 at 12:00 am)

U WANTED US TO NOT BEING A ROBOT AND I FINALY UNDERSTANT U WHEN U TAKE THE DIRIVATIVE OF PSI AT THE END AND SHOW US ITS THE SAME

edd9139 (November 30, 1999 at 12:00 am)

Thanks

ryanguy6789 (November 30, 1999 at 12:00 am)

good stuff!

Mubasher77 (November 30, 1999 at 12:00 am)

well this method is much mechanical and i have to say its brilliant but i m worried about my teachers solution about the Exact DE, as she says y=∫Mdx +∫ (terms of N containing y)dy, i cant make sure the relation between your solution and my teachers,,can u deifne a little bit that formula???????????/

Mubasher77 (November 30, 1999 at 12:00 am)

well this method is much mechanical and i have to say its brilliant but i m worried about my teachers solution about the Exact DE, as she says y=∫Mdx +∫ (terms of N containing y)dy, i cant make sure the relation between your solution and my teachers,,can u deifne a little bit that formula???????????/